redis localhost:6379> sadd userlist 1
(integer) 1
redis localhost:6379> sadd userlist 2
(integer) 1
redis localhost:6379> sadd userlist 3
(integer) 1
redis localhost:6379> sadd userlist 4
(integer) 1
redis localhost:6379> sadd userlist 5
(integer) 1
redis localhost:6379> set score:user:1 20
OK
redis localhost:6379> set score:user:2 15
OK
redis localhost:6379> set score:user:3 11
OK
redis localhost:6379> set score:user:4 24
OK
redis localhost:6379> set score:user:5 15
OK
redis localhost:6379> set age:user:1 29
OK
redis localhost:6379> set age:user:2 35
OK
redis localhost:6379> set age:user:3 25
OK
redis localhost:6379> set age:user:4 31
OK
redis localhost:6379> set age:user:5 27
OK
如上redis结构，如何实现sort的时候根据score倒排序，如果score相等（上面user2和user5的score相等），那么按照age正排序？
期望最后得到的userid排序结果为:
4
1
5
2
3
请问各位：这样的命令该如何写，或者有没有比较好的解决方案
